What is the calculated volume deficit in a 65-pound dog with 5% dehydration?

To calculate the volume deficit due to dehydration, the formula involves knowing the weight of the dog and the percentage of dehydration.

First, convert the dog's weight from pounds to kilograms. Since 1 pound is approximately 0.453592 kilograms, a 65-pound dog weighs about 29.5 kilograms (65 lbs x 0.453592 = 29.5 kg).

Next, to find the volume deficit for a 5% dehydration level, you can use the formula:

Volume deficit (mL) = Body weight (kg) x Percentage of dehydration.

Thus, for a 65-pound (29.5 kg) dog with 5% dehydration:

Volume deficit = 29.5 kg x 0.05 (5%) = 1.475 liters.

Since 1 liter is equal to 1000 mL, this converts to:

1.475 liters x 1000 mL/liter = 1475 mL.

When rounding, this is approximately 1500 mL; hence, the calculated volume deficit for a 65-pound dog with 5% dehydration is accurately represented by the choice indicating 1500 mL.